7p-4p^2=3

Solution for 7p-4p^2=3 equation:

7p-4p^2=3

We move all terms to the left:

7p-4p^2-(3)=0

a = -4; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·(-4)·(-3)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*-4}=\frac{-8}{-8}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*-4}=\frac{-6}{-8}
=3/4
$